NAME
stpcpy - copy a string returning a pointer to its end
SYNOPSIS
#define _GNU_SOURCE
#include <string.h>
char *stpcpy(char *dest, const char *src);
DESCRIPTION
The
stpcpy() function copies the string pointed to by
src
(including the terminating `\0' character) to the array pointed to by
dest. The strings may not overlap, and the destination string
dest must be large enough to receive the copy.
RETURN VALUE
stpcpy() returns a pointer to the
end of the string
dest (that is, the address of the terminating null character)
rather than the beginning.
EXAMPLE
For example, this program uses
stpcpy to concatenate
foo and
bar to produce
foobar, which it then prints.
#include <string.h>
int
main (void)
{
char *to = buffer;
to = stpcpy (to, "foo");
to = stpcpy (to, "bar");
printf ("%s\n", buffer);
}
CONFORMING TO
This function is not part of the ANSI or POSIX standards, and is
not customary on Unix systems, but is not a GNU invention either.
Perhaps it comes from MS-DOS.
SEE ALSO
strcpy(3),
bcopy(3),
memccpy(3),
memcpy(3),
memmove(3)
Index
- NAME
-
- SYNOPSIS
-
- DESCRIPTION
-
- RETURN VALUE
-
- EXAMPLE
-
- CONFORMING TO
-
- SEE ALSO
-